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Old 02-15-2008, 11:09 AM
Ronald J Marchand
 
Posts: n/a
Default Re: Copying Directory Structures

"Joe Burns" <joeburns@callageek.com> wrote in message
news:YgmTa.25140$b03.24330@lakeread03...
> I have never done that in SCO. Can you, or someone else, give me the
> command to do so? I also need to ensure that all of the privileges and
> ownerships remain the same.
>
> Thank you,
>
> Joe Burns
>

This group takes a "dim" view of top posting.

Start by reading "man nfs" and "man exports". This should get you started
on the yellow brick road. Then if you have a specific question, just ask
away.

Ron


> "Ronald J Marchand" <rojomar@covad.net> wrote in message
> news:bfjah8$sse$1@sun-news.laserlink.net...
> > "Joe Burns" <joeburns@callageek.com> wrote in message
> > news:tF9Ta.23684$b03.1019@lakeread03...
> > > I am in the process of converting a customer from an old SCO 5.0.5

> server
> > > (they have been running this hardware for about 10 years) to a new

> server
> > > running SCO 5.0.6. I have the new SCO Enterprise version installed

and
> > can
> > > do a "rlogin" across the network to the other system. Now I need to

> copy
> > > the entire contents, with the same file ownerships, groups, etc

intact,
> > from
> > > the old system to the new system. I can't remember how to do that. I
> > > believe that I used to use UUCP between servers when I would dial-up

> from
> > > one city to the other (about 10 years ago), but I never had to do this
> > > process across an Ethernet connection. Would I use "uucp" or "rcp" or
> > > something else? What is the syntax of the command. Let's say, for

the
> > > purposes of this example, that the names of the systems are

"oldsystem"
> > and
> > > "newsystem" and the IP addresses are 192.168.1.1 and 192.168.1.2
> > > respectively.
> > >
> > > Thank you for any help you can give.
> > >
> > > Joe Burns, President
> > > CompuGeek, L.L.C.

> >
> > If the two machines are on the same local network, why not mount the
> > directory of the first machine to the second and just 'copy' at will?
> >
> > Ron



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