Hi,

I'm trying to use the result of a conditional statement in a where
clause, but i'm getting 1)nowhere 2) desperate :-)

The query is simple:
--------
SELECT
idUser,
(@ageraw:=YEAR(CURRENT_DATE()) - YEAR(dateofbirth) -
(RIGHT(CURRENT_DATE(),5)<'12-31')) AS temp,
@age:=if( @ageraw > 100,0,
if( @ageraw < 10,0 ,
@ageraw
)) as age
from users u
---------

this works as a charm. But now I want to select users of a certain
age, and I add a where clause:
from users u having @age<50

This is not working. Nor is any other variant I can think of. How can
this be achieved?

greeting, and many thanks,

Paul

> @age:=if( @ageraw > 100,0,
> if( @ageraw < 10,0 ,
> @ageraw
> )) as age
>
> this works as a charm. But now I want to select users of a certain
> age, and I add a where clause:
> from users u having @age<50

As the fields is named "age", HAVING age<50 is what I would type. With
the @ character, you call the contents of the variable, not the contents
of a record field.

Best regards
--
Willem Bogaerts

Application smith
Kratz B.V.
http://www.kratz.nl/

Hi Willem

> As the fields is named "age", HAVING age<50 is what I would type. With
> the @ character, you call the contents of the variable, not the contents
> of a record field.

Thanks for your reply. However, that does not work :-((
I get a syntaxerror....

any more idea's?

Paul

On 31 jan, 09:53, "profke" <pwieg...@gmail.com> wrote:
> Hi Willem
>
> > As the fields is named "age", HAVING age<50 is what I would type. With
> > the @ character, you call the contents of the variable, not the contents
> > of a record field.
>
> Thanks for your reply. However, that does not work :-((
> I get a syntaxerror....

Well, not a syntax error.. i get a unknown field error...