Unix Technical Forum

How to query and index for customer with lastname and city

This is a discussion on How to query and index for customer with lastname and city within the Pgsql Performance forums, part of the PostgreSQL category; --> Hi, I have two tables: Customer: objectid, lastname, fk_address Address: objectid, city I want to select all customers with ...


Go Back   Unix Technical Forum > Database Server Software > PostgreSQL > Pgsql Performance

FAQ Members List Calendar Search Today's Posts Mark Forums Read
  #1 (permalink)  
Old 04-19-2008, 08:13 AM
Joost Kraaijeveld
 
Posts: n/a
Default How to query and index for customer with lastname and city

Hi,

I have two tables:

Customer: objectid, lastname, fk_address
Address: objectid, city

I want to select all customers with a name >= some_name and living in a
city >= some_city, all comparisons case insensitive

Below is what I actually have. Given the fact that it takes forever to
get a result (> 6 seconds) , there must be something wrong with my
solution or my expectation. Can anyone tell what I should do to make
this query go faster ( or convince me to wait for the result ;-()?


SELECT customers.objectid FROM prototype.customers,prototype.addresses
WHERE
customers.contactAddress = addresses.objectId
AND
(
TRIM(UPPER(lastName)) >= TRIM(UPPER('some_name'))
AND
TRIM(UPPER(city)) >= TRIM(UPPER('some_city'))
)
order by TRIM(UPPER(lastname)), TRIM(UPPER(city))

Explain analyze after a full alayse vacuum:

Sort (cost=54710.68..54954.39 rows=97484 width=111) (actual
time=7398.971..7680.405 rows=96041 loops=1)
Sort Key: btrim(upper(customers.lastname)),
btrim(upper(addresses.city))
-> Hash Join (cost=14341.12..46632.73 rows=97484 width=111) (actual
time=1068.862..5472.788 rows=96041 loops=1)
Hash Cond: ("outer".contactaddress = "inner".objectid)
-> Seq Scan on customers (cost=0.00..24094.01 rows=227197
width=116) (actual time=0.018..1902.646 rows=223990 loops=1)
Filter: (btrim(upper(lastname)) >= 'JANSEN'::text)
-> Hash (cost=13944.94..13944.94 rows=158473 width=75) (actual
time=1068.467..1068.467 rows=158003 loops=1)
-> Bitmap Heap Scan on addresses (cost=1189.66..13944.94
rows=158473 width=75) (actual time=71.259..530.986 rows=158003 loops=1)
Recheck Cond: (btrim(upper(city)) >=
'NIJMEGEN'::text)
-> Bitmap Index Scan on
prototype_addresses_trim_upper_city (cost=0.00..1189.66 rows=158473
width=0) (actual time=68.290..68.290 rows=158003 loops=1)
Index Cond: (btrim(upper(city)) >=
'NIJMEGEN'::text)
Total runtime: 7941.095 ms


I have indices on :
fki_customers_addresses
customer.lastname (both lastname and trim(uppercase(lastname))
addresses.city (both city and trim(uppercase(city))

I


--
Groeten,

Joost Kraaijeveld
Askesis B.V.
Molukkenstraat 14
6524NB Nijmegen
tel: 024-3888063 / 06-51855277
fax: 024-3608416
e-mail: J.Kraaijeveld@Askesis.nl
web: www.askesis.nl


Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #2 (permalink)  
Old 04-19-2008, 08:13 AM
hubert depesz lubaczewski
 
Posts: n/a
Default Re: How to query and index for customer with lastname and city

On 3/4/06, Joost Kraaijeveld <J.Kraaijeveld@askesis.nl> wrote:
> Below is what I actually have. Given the fact that it takes forever to get
> a result (> 6 seconds) , there must be something wrong with my solution or
> my expectation. Can anyone tell what I should do to make this query go
> faster ( or convince me to wait for the result ;-()?
> Explain analyze after a full alayse vacuum:
> Sort (cost=54710.68..54954.39 rows=97484 width=111) (actual
> time=7398.971..7680.405 rows=96041 loops=1)
> Sort Key: btrim(upper(customers.lastname)), btrim(upper(addresses.city))
> -> Hash Join (cost=14341.12..46632.73 rows=97484 width=111) (actual
> time=1068.862..5472.788 rows=96041 loops=1)
> Hash Cond: ("outer".contactaddress = "inner".objectid)
> -> Seq Scan on customers (cost=0.00..24094.01 rows=227197
> width=116) (actual time=0.018..1902.646 rows=223990 loops=1)
> Filter: (btrim(upper(lastname)) >= 'JANSEN'::text)
> -> Hash (cost=13944.94..13944.94 rows=158473 width=75) (actual
> time=1068.467..1068.467 rows=158003 loops=1)
> -> Bitmap Heap Scan on addresses (cost=1189.66..13944.94
> rows=158473 width=75) (actual time=71.259..530.986 rows=158003 loops=1)
> Recheck Cond: (btrim(upper(city)) >= 'NIJMEGEN'::text)
> -> Bitmap Index Scan on
> prototype_addresses_trim_upper_city (cost=0.00..1189.66
> rows=158473 width=0) (actual time=68.290..68.290 rows=158003 loops=1)
> Index Cond: (btrim(upper(city)) >=
> 'NIJMEGEN'::text)
> Total runtime: 7941.095 ms


explain clearly shows, that index is used for addresses scan, but it
is not so for users.
explain estimates that 227197 customers match the lastname criteria -
which looks awfuly high.
how many record do you have in the customers table?

i would try to create index test on customers(contactAddress,
trim(uppercase(lastname)));
or with other ordring of fields.

try this - create the index, make analyze of customers table, and
recheck explain.
then try the second index in the same manner.

maybe this could of some help...

depesz

---------------------------(end of broadcast)---------------------------
TIP 6: explain analyze is your friend

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #3 (permalink)  
Old 04-19-2008, 08:13 AM
Joost Kraaijeveld
 
Posts: n/a
Default Re: How to query and index for customer with lastname

Hi Hubert,

On Sat, 2006-03-04 at 14:49 +0100, hubert depesz lubaczewski wrote:
> > Sort (cost=54710.68..54954.39 rows=97484 width=111) (actual
> > time=7398.971..7680.405 rows=96041 loops=1)
> > Sort Key: btrim(upper(customers.lastname)), btrim(upper(addresses.city))
> > -> Hash Join (cost=14341.12..46632.73 rows=97484 width=111) (actual time=1068.862..5472.788 rows=96041 loops=1)
> > Hash Cond: ("outer".contactaddress = "inner".objectid)
> > -> Seq Scan on customers (cost=0.00..24094.01 rows=227197 width=116) (actual time=0.018..1902.646 rows=223990 loops=1)
> > Filter: (btrim(upper(lastname)) >= 'JANSEN'::text)
> > -> Hash (cost=13944.94..13944.94 rows=158473 width=75) (actual time=1068.467..1068.467 rows=158003 loops=1)
> > -> Bitmap Heap Scan on addresses (cost=1189.66..13944.94 rows=158473 width=75) (actual time=71.259..530.986 rows=158003 loops=1)
> > Recheck Cond: (btrim(upper(city)) >= 'NIJMEGEN'::text)
> > -> Bitmap Index Scan on prototype_addresses_trim_upper_city (cost=0.00..1189.66 rows=158473 width=0) (actual time=68.290..68.290 rows=158003 loops=1)
> > Index Cond: (btrim(upper(city)) >=> 'NIJMEGEN'::text)
> > Total runtime: 7941.095 ms

>
> explain clearly shows, that index is used for addresses scan, but it

Yes, but I do not understand why I have both a "Bitmap Index Scan" and
a "Bitmap Heap Scan" on (btrim(upper(city)) >=> 'NIJMEGEN'::text)?

> is not so for users.
> explain estimates that 227197 customers match the lastname criteria -
> which looks awfuly high.
> how many record do you have in the customers table?

368915 of which 222465 actually meet the condition.

>From what I understand from the mailing list, PostgreSQL prefers a table

scan whenever it expects that the number of records in the resultset
will be ~ > 10 % of the total number of records in the table. Which
explains the table scan for customers, but than again, it does not
explain why it uses the index on addresses: it has 369337 addresses of
which 158003 meet the condition

> i would try to create index test on customers(contactAddress,
> trim(uppercase(lastname)));
> or with other ordring of fields.
>
> try this - create the index, make analyze of customers table, and
> recheck explain.
> then try the second index in the same manner.

Makes no difference.


--
Groeten,

Joost Kraaijeveld
Askesis B.V.
Molukkenstraat 14
6524NB Nijmegen
tel: 024-3888063 / 06-51855277
fax: 024-3608416
e-mail: J.Kraaijeveld@Askesis.nl
web: www.askesis.nl


---------------------------(end of broadcast)---------------------------
TIP 1: if posting/reading through Usenet, please send an appropriate
subscribe-nomail command to majordomo@postgresql.org so that your
message can get through to the mailing list cleanly

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #4 (permalink)  
Old 04-19-2008, 08:13 AM
hubert depesz lubaczewski
 
Posts: n/a
Default Re: How to query and index for customer with lastname and city

On 3/4/06, Joost Kraaijeveld <J.Kraaijeveld@askesis.nl> wrote:
> > how many record do you have in the customers table?

> 368915 of which 222465 actually meet the condition.
> >From what I understand from the mailing list, PostgreSQL prefers a table

> scan whenever it expects that the number of records in the resultset
> will be ~ > 10 % of the total number of records in the table. Which
> explains the table scan for customers, but than again, it does not
> explain why it uses the index on addresses: it has 369337 addresses of
> which 158003 meet the condition



bitmap index scan is faster than sequential table scan. that's all. it
was introduced in 8.1 as far as i remember.
basically - i doubt if you can get better performace from query when
the result row-count is that high.

out of curiosity though - why do you need so many rows? it's not
possible to view them, nor do anything meaningful with 200 thousand
rows!

depesz

---------------------------(end of broadcast)---------------------------
TIP 9: In versions below 8.0, the planner will ignore your desire to
choose an index scan if your joining column's datatypes do not
match

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
  #5 (permalink)  
Old 04-19-2008, 08:13 AM
Kevin Brown
 
Posts: n/a
Default Re: How to query and index for customer with lastname and city

On Saturday 04 March 2006 08:23, hubert depesz lubaczewski wrote:
> On 3/4/06, Joost Kraaijeveld <J.Kraaijeveld@askesis.nl> wrote:
> > > how many record do you have in the customers table?

> >
> > 368915 of which 222465 actually meet the condition.
> >
> > >From what I understand from the mailing list, PostgreSQL prefers a table

> >
> > scan whenever it expects that the number of records in the resultset
> > will be ~ > 10 % of the total number of records in the table. Which
> > explains the table scan for customers, but than again, it does not
> > explain why it uses the index on addresses: it has 369337 addresses of
> > which 158003 meet the condition

>
> bitmap index scan is faster than sequential table scan. that's all. it
> was introduced in 8.1 as far as i remember.
> basically - i doubt if you can get better performace from query when
> the result row-count is that high.
>
> out of curiosity though - why do you need so many rows? it's not
> possible to view them, nor do anything meaningful with 200 thousand
> rows!
>
> depesz


If you're just displaying, use limit and offset to grab one page at a time.
If you're manipulating it would be a good idea to do something in a stored
procedure.

---------------------------(end of broadcast)---------------------------
TIP 1: if posting/reading through Usenet, please send an appropriate
subscribe-nomail command to majordomo@postgresql.org so that your
message can get through to the mailing list cleanly

Digg this Post!Add Post to del.icio.usBookmark Post in TechnoratiFurl this Post!
Reply With Quote
Reply


Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On
Forum Jump


All times are GMT. The time now is 04:39 AM.


Powered by vBulletin® Version 3.6.5
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.
Search Engine Optimization by vBSEO 3.2.0
www.UnixAdminTalk.com